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3x^2=630
We move all terms to the left:
3x^2-(630)=0
a = 3; b = 0; c = -630;
Δ = b2-4ac
Δ = 02-4·3·(-630)
Δ = 7560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7560}=\sqrt{36*210}=\sqrt{36}*\sqrt{210}=6\sqrt{210}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{210}}{2*3}=\frac{0-6\sqrt{210}}{6} =-\frac{6\sqrt{210}}{6} =-\sqrt{210} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{210}}{2*3}=\frac{0+6\sqrt{210}}{6} =\frac{6\sqrt{210}}{6} =\sqrt{210} $
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